Base | Representation |
---|---|
bin | 10010110110101100… |
… | …00001011110000001 |
3 | 222010110010221121000 |
4 | 21123112001132001 |
5 | 131212320400213 |
6 | 4352234522213 |
7 | 505562162436 |
oct | 113326013601 |
9 | 28113127530 |
10 | 10122434433 |
11 | 43249398a1 |
12 | 1b65b96369 |
13 | c54187497 |
14 | 6c0513b8d |
15 | 3e39e4c73 |
hex | 25b581781 |
10122434433 has 64 divisors (see below), whose sum is σ = 16736051200. Its totient is φ = 6019323840.
The previous prime is 10122434431. The next prime is 10122434447. The reversal of 10122434433 is 33443422101.
10122434433 is a `hidden beast` number, since 1 + 0 + 1 + 224 + 3 + 4 + 433 = 666.
It is not a de Polignac number, because 10122434433 - 21 = 10122434431 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 10122434397 and 10122434406.
It is not an unprimeable number, because it can be changed into a prime (10122434431) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 579810 + ... + 597012.
It is an arithmetic number, because the mean of its divisors is an integer number (261500800).
Almost surely, 210122434433 is an apocalyptic number.
It is an amenable number.
10122434433 is a deficient number, since it is larger than the sum of its proper divisors (6613616767).
10122434433 is a wasteful number, since it uses less digits than its factorization.
10122434433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17299 (or 17293 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 10122434433 its reverse (33443422101), we get a palindrome (43565856534).
The spelling of 10122434433 in words is "ten billion, one hundred twenty-two million, four hundred thirty-four thousand, four hundred thirty-three".
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