10123010020113 has 4 divisors (see below), whose sum is σ = 13497346693488. Its totient is φ = 6748673346740.

The previous prime is 10123010020103. The next prime is 10123010020117. The reversal of 10123010020113 is 31102001032101.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10123010020113 - 2⁹ = 10123010019601 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10123010020092 and 10123010020101.

It is not an unprimeable number, because it can be changed into a prime (10123010020117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1687168336683 + ... + 1687168336688.

It is an arithmetic number, because the mean of its divisors is an integer number (3374336673372).

Almost surely, 2^{10123010020113} is an apocalyptic number.

It is an amenable number.

10123010020113 is a deficient number, since it is larger than the sum of its proper divisors (3374336673375).

10123010020113 is an equidigital number, since it uses as much as digits as its factorization.

10123010020113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3374336673374.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 10123010020113 its reverse (31102001032101), we get a palindrome (41225011052214).

The spelling of 10123010020113 in words is "ten trillion, one hundred twenty-three billion, ten million, twenty thousand, one hundred thirteen".