Search a number
-
+
101230102113 = 3717283557709
BaseRepresentation
bin101111001000111001…
…0001100011001100001
3100200021220022000010020
41132101302030121201
53124304401231423
6114300544224053
710212401446020
oct1362162143141
9320256260106
10101230102113
1139a27832018
121775190b029
13971361350a
144c845888b7
15297721e4e3
hex1791c8c661

101230102113 has 16 divisors (see below), whose sum is σ = 163329240960. Its totient is φ = 54443079936.

The previous prime is 101230102111. The next prime is 101230102187. The reversal of 101230102113 is 311201032101.

It is a happy number.

It is not a de Polignac number, because 101230102113 - 21 = 101230102111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101230102092 and 101230102101.

It is not an unprimeable number, because it can be changed into a prime (101230102111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 141778498 + ... + 141779211.

It is an arithmetic number, because the mean of its divisors is an integer number (10208077560).

Almost surely, 2101230102113 is an apocalyptic number.

It is an amenable number.

101230102113 is a deficient number, since it is larger than the sum of its proper divisors (62099138847).

101230102113 is a wasteful number, since it uses less digits than its factorization.

101230102113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 283557736.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 101230102113 its reverse (311201032101), we get a palindrome (412431134214).

The spelling of 101230102113 in words is "one hundred one billion, two hundred thirty million, one hundred two thousand, one hundred thirteen".

Divisors: 1 3 7 17 21 51 119 357 283557709 850673127 1984903963 4820481053 5954711889 14461443159 33743367371 101230102113