10123031120131 has 2 divisors, whose sum is σ = 10123031120132. Its totient is φ = 10123031120130.

The previous prime is 10123031120119. The next prime is 10123031120149. The reversal of 10123031120131 is 13102113032101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10123031120131 - 2²¹ = 10123029022979 is a prime.

It is a super-2 number, since 2×10123031120131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10123031120099 and 10123031120108.

It is not a weakly prime, because it can be changed into another prime (10123031120431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5061515560065 + 5061515560066.

It is an arithmetic number, because the mean of its divisors is an integer number (5061515560066).

Almost surely, 2^{10123031120131} is an apocalyptic number.

10123031120131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10123031120131 is an equidigital number, since it uses as much as digits as its factorization.

10123031120131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 10123031120131 its reverse (13102113032101), we get a palindrome (23225144152232).

The spelling of 10123031120131 in words is "ten trillion, one hundred twenty-three billion, thirty-one million, one hundred twenty thousand, one hundred thirty-one".