Base | Representation |
---|---|
bin | 1001001101001111001110… |
… | …1011001000100011110111 |
3 | 1022211202022102222201102221 |
4 | 2103103303223020203313 |
5 | 2311323431431320434 |
6 | 33310242320543211 |
7 | 2063236101534511 |
oct | 223236353104367 |
9 | 38752272881387 |
10 | 10123031120119 |
11 | 3253176184595 |
12 | 1175ab2781b07 |
13 | 5857a0301b98 |
14 | 26dd58c5cbb1 |
15 | 1284cb0882b4 |
hex | 934f3ac88f7 |
10123031120119 has 2 divisors, whose sum is σ = 10123031120120. Its totient is φ = 10123031120118.
The previous prime is 10123031120117. The next prime is 10123031120131. The reversal of 10123031120119 is 91102113032101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10123031120119 - 21 = 10123031120117 is a prime.
It is a super-2 number, since 2×101230311201192 (a number of 27 digits) contains 22 as substring.
Together with 10123031120117, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 10123031120093 and 10123031120102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10123031120117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5061515560059 + 5061515560060.
It is an arithmetic number, because the mean of its divisors is an integer number (5061515560060).
Almost surely, 210123031120119 is an apocalyptic number.
10123031120119 is a deficient number, since it is larger than the sum of its proper divisors (1).
10123031120119 is an equidigital number, since it uses as much as digits as its factorization.
10123031120119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 25.
The spelling of 10123031120119 in words is "ten trillion, one hundred twenty-three billion, thirty-one million, one hundred twenty thousand, one hundred nineteen".
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