101232113131 has 8 divisors (see below), whose sum is σ = 102043579904. Its totient is φ = 100420871040.

The previous prime is 101232113123. The next prime is 101232113141. The reversal of 101232113131 is 131311232101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 101232113131 - 2³ = 101232113123 is a prime.

It is a super-2 number, since 2×101232113131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101232113099 and 101232113108.

It is not an unprimeable number, because it can be changed into a prime (101232113141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 915571 + ... + 1020163.

It is an arithmetic number, because the mean of its divisors is an integer number (12755447488).

Almost surely, 2^101232113131 is an apocalyptic number.

101232113131 is a deficient number, since it is larger than the sum of its proper divisors (811466773).

101232113131 is a wasteful number, since it uses less digits than its factorization.

101232113131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 112341.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 101232113131 its reverse (131311232101), we get a palindrome (232543345232).

The spelling of 101232113131 in words is "one hundred one billion, two hundred thirty-two million, one hundred thirteen thousand, one hundred thirty-one".