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101232113141 is a prime number
BaseRepresentation
bin101111001000111100…
…1110111010111110101
3100200022001002011201202
41132101321313113311
53124310410110031
6114301055302245
710212424523045
oct1362171672765
9320261064652
10101232113141
1139a28985a25
121775251a985
139713b68983
144c8494d725
1529774ba2cb
hex1791e775f5

101232113141 has 2 divisors, whose sum is σ = 101232113142. Its totient is φ = 101232113140.

The previous prime is 101232113123. The next prime is 101232113159. The reversal of 101232113141 is 141311232101.

It is a balanced prime because it is at equal distance from previous prime (101232113123) and next prime (101232113159).

It can be written as a sum of positive squares in only one way, i.e., 68668106116 + 32564007025 = 262046^2 + 180455^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-101232113141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101232113441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50616056570 + 50616056571.

It is an arithmetic number, because the mean of its divisors is an integer number (50616056571).

Almost surely, 2101232113141 is an apocalyptic number.

It is an amenable number.

101232113141 is a deficient number, since it is larger than the sum of its proper divisors (1).

101232113141 is an equidigital number, since it uses as much as digits as its factorization.

101232113141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 101232113141 its reverse (141311232101), we get a palindrome (242543345242).

The spelling of 101232113141 in words is "one hundred one billion, two hundred thirty-two million, one hundred thirteen thousand, one hundred forty-one".