Base | Representation |
---|---|
bin | 10111000001000111110000… |
… | …101111010011010110101111 |
3 | 111021102200210201100210021021 |
4 | 113001013300233103112233 |
5 | 101232041342010200221 |
6 | 555145221221315011 |
7 | 30215531245021324 |
oct | 2701076057232657 |
9 | 437380721323237 |
10 | 101232123131311 |
11 | 2a28a336434277 |
12 | b42b569265a67 |
13 | 44641c0922353 |
14 | 1add937732b4b |
15 | ba842e6ba041 |
hex | 5c11f0bd35af |
101232123131311 has 2 divisors, whose sum is σ = 101232123131312. Its totient is φ = 101232123131310.
The previous prime is 101232123131203. The next prime is 101232123131317. The reversal of 101232123131311 is 113131321232101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101232123131311 - 233 = 101223533196719 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101232123131317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50616061565655 + 50616061565656.
It is an arithmetic number, because the mean of its divisors is an integer number (50616061565656).
Almost surely, 2101232123131311 is an apocalyptic number.
101232123131311 is a deficient number, since it is larger than the sum of its proper divisors (1).
101232123131311 is an equidigital number, since it uses as much as digits as its factorization.
101232123131311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 25.
Adding to 101232123131311 its reverse (113131321232101), we get a palindrome (214363444363412).
The spelling of 101232123131311 in words is "one hundred one trillion, two hundred thirty-two billion, one hundred twenty-three million, one hundred thirty-one thousand, three hundred eleven".
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