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10123303113113 = 599154131096499
BaseRepresentation
bin1001001101010000001111…
…1000101101000110011001
31022211210000101210101200112
42103110003320231012121
52311330011044104423
633310325314414105
72063245613456141
oct223240370550631
938753011711615
1010123303113113
1132532a5769993
121175b69891335
13585814774b98
1426dd83021921
151284e4db3a78
hex93503e2d199

10123303113113 has 8 divisors (see below), whose sum is σ = 10140870600000. Its totient is φ = 10105737851248.

The previous prime is 10123303113073. The next prime is 10123303113139. The reversal of 10123303113113 is 31131130332101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10123303113113 - 214 = 10123303096729 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10123303113173) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8684138 + ... + 9780636.

It is an arithmetic number, because the mean of its divisors is an integer number (1267608825000).

Almost surely, 210123303113113 is an apocalyptic number.

It is an amenable number.

10123303113113 is a deficient number, since it is larger than the sum of its proper divisors (17567486887).

10123303113113 is a wasteful number, since it uses less digits than its factorization.

10123303113113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1112511.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 10123303113113 its reverse (31131130332101), we get a palindrome (41254433445214).

The spelling of 10123303113113 in words is "ten trillion, one hundred twenty-three billion, three hundred three million, one hundred thirteen thousand, one hundred thirteen".

Divisors: 1 599 15413 1096499 9232387 656802901 16900339087 10123303113113