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101240130002441 is a prime number
BaseRepresentation
bin10111000001001111001101…
…111111000101111000001001
3111021110110110201200222120212
4113001033031333011320021
5101232204241240034231
6555153023524330505
730216233541220043
oct2701171577057011
9437413421628525
10101240130002441
112a292775075041
12b431022843a35
134464b986ccb11
141b00096ca8a93
15ba874c5c142b
hex5c13cdfc5e09

101240130002441 has 2 divisors, whose sum is σ = 101240130002442. Its totient is φ = 101240130002440.

The previous prime is 101240130002273. The next prime is 101240130002507. The reversal of 101240130002441 is 144200031042101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 80145537379216 + 21094592623225 = 8952404^2 + 4592885^2 .

It is a cyclic number.

It is not a de Polignac number, because 101240130002441 - 218 = 101240129740297 is a prime.

It is a super-2 number, since 2×1012401300024412 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (101240130004441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50620065001220 + 50620065001221.

It is an arithmetic number, because the mean of its divisors is an integer number (50620065001221).

Almost surely, 2101240130002441 is an apocalyptic number.

It is an amenable number.

101240130002441 is a deficient number, since it is larger than the sum of its proper divisors (1).

101240130002441 is an equidigital number, since it uses as much as digits as its factorization.

101240130002441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 101240130002441 its reverse (144200031042101), we get a palindrome (245440161044542).

The spelling of 101240130002441 in words is "one hundred one trillion, two hundred forty billion, one hundred thirty million, two thousand, four hundred forty-one".