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101243543411953 is a prime number
BaseRepresentation
bin10111000001010010011001…
…011100001101110011110001
3111021110210021121122011011101
4113001102121130031303301
5101232233234103140303
6555154350341444401
730216414246554215
oct2701223134156361
9437423247564141
10101243543411953
112a29416692a138
12b431815a10701
1344652c093c367
141b002dc366945
15ba889c0c6d1d
hex5c149970dcf1

101243543411953 has 2 divisors, whose sum is σ = 101243543411954. Its totient is φ = 101243543411952.

The previous prime is 101243543411947. The next prime is 101243543412043. The reversal of 101243543411953 is 359114345342101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 50975273251809 + 50268270160144 = 7139697^2 + 7090012^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-101243543411953 is a prime.

It is not a weakly prime, because it can be changed into another prime (101243543415953) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50621771705976 + 50621771705977.

It is an arithmetic number, because the mean of its divisors is an integer number (50621771705977).

Almost surely, 2101243543411953 is an apocalyptic number.

It is an amenable number.

101243543411953 is a deficient number, since it is larger than the sum of its proper divisors (1).

101243543411953 is an equidigital number, since it uses as much as digits as its factorization.

101243543411953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 777600, while the sum is 46.

The spelling of 101243543411953 in words is "one hundred one trillion, two hundred forty-three billion, five hundred forty-three million, four hundred eleven thousand, nine hundred fifty-three".