Base | Representation |
---|---|
bin | 101111001001100100… |
… | …1111110110110101011 |
3 | 100200100111121012021202 |
4 | 1132103021332312223 |
5 | 3124331244142212 |
6 | 114303125354415 |
7 | 10213101164621 |
oct | 1362311766653 |
9 | 320314535252 |
10 | 101253115307 |
11 | 39a39820193 |
12 | 17759568a0b |
13 | 97183102a6 |
14 | 4c87659511 |
15 | 29792680c2 |
hex | 179327edab |
101253115307 has 2 divisors, whose sum is σ = 101253115308. Its totient is φ = 101253115306.
The previous prime is 101253115297. The next prime is 101253115333. The reversal of 101253115307 is 703511352101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 101253115307 - 214 = 101253098923 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 101253115307.
It is not a weakly prime, because it can be changed into another prime (101253115907) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50626557653 + 50626557654.
It is an arithmetic number, because the mean of its divisors is an integer number (50626557654).
Almost surely, 2101253115307 is an apocalyptic number.
101253115307 is a deficient number, since it is larger than the sum of its proper divisors (1).
101253115307 is an equidigital number, since it uses as much as digits as its factorization.
101253115307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3150, while the sum is 29.
Adding to 101253115307 its reverse (703511352101), we get a palindrome (804764467408).
The spelling of 101253115307 in words is "one hundred one billion, two hundred fifty-three million, one hundred fifteen thousand, three hundred seven".
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