Base | Representation |
---|---|
bin | 10111000010000110111111… |
… | …010011000011111010111101 |
3 | 111021200012001002100121102201 |
4 | 113002012333103003322331 |
5 | 101234144411324334323 |
6 | 555240330015351501 |
7 | 30223453521303124 |
oct | 2702067723037275 |
9 | 437605032317381 |
10 | 101300013121213 |
11 | 2a306104580545 |
12 | b440755522591 |
13 | 446a71cb857ca |
14 | 1b02d38014abb |
15 | baa0a49378ad |
hex | 5c21bf4c3ebd |
101300013121213 has 2 divisors, whose sum is σ = 101300013121214. Its totient is φ = 101300013121212.
The previous prime is 101300013121201. The next prime is 101300013121339. The reversal of 101300013121213 is 312121310003101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 95786993648889 + 5513019472324 = 9787083^2 + 2347982^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-101300013121213 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101300013124213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50650006560606 + 50650006560607.
It is an arithmetic number, because the mean of its divisors is an integer number (50650006560607).
Almost surely, 2101300013121213 is an apocalyptic number.
It is an amenable number.
101300013121213 is a deficient number, since it is larger than the sum of its proper divisors (1).
101300013121213 is an equidigital number, since it uses as much as digits as its factorization.
101300013121213 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 101300013121213 its reverse (312121310003101), we get a palindrome (413421323124314).
The spelling of 101300013121213 in words is "one hundred one trillion, three hundred billion, thirteen million, one hundred twenty-one thousand, two hundred thirteen".
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