Base | Representation |
---|---|
bin | 10111000010000111000101… |
… | …001001010010100101001001 |
3 | 111021200012021220221200221102 |
4 | 113002013011021102211021 |
5 | 101234200111433114423 |
6 | 555240343442151145 |
7 | 30223456122201365 |
oct | 2702070511224511 |
9 | 437605256850842 |
10 | 101300111223113 |
11 | 2a3061549959a0 |
12 | b4407823524b5 |
13 | 446a7372b337a |
14 | 1b02d470702a5 |
15 | baa0ad364c28 |
hex | 5c21c5252949 |
101300111223113 has 64 divisors (see below), whose sum is σ = 114057101942784. Its totient is φ = 89191113984000.
The previous prime is 101300111223023. The next prime is 101300111223119. The reversal of 101300111223113 is 311322111003101.
It is a cyclic number.
It is not a de Polignac number, because 101300111223113 - 230 = 101299037481289 is a prime.
It is not an unprimeable number, because it can be changed into a prime (101300111223119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 23651669870 + ... + 23651674152.
It is an arithmetic number, because the mean of its divisors is an integer number (1782142217856).
Almost surely, 2101300111223113 is an apocalyptic number.
It is an amenable number.
101300111223113 is a deficient number, since it is larger than the sum of its proper divisors (12756990719671).
101300111223113 is a wasteful number, since it uses less digits than its factorization.
101300111223113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6006.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 101300111223113 its reverse (311322111003101), we get a palindrome (412622222226214).
The spelling of 101300111223113 in words is "one hundred one trillion, three hundred billion, one hundred eleven million, two hundred twenty-three thousand, one hundred thirteen".
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