10130012113 has 4 divisors (see below), whose sum is σ = 10909243828. Its totient is φ = 9350780400.

The previous prime is 10130012099. The next prime is 10130012141. The reversal of 10130012113 is 31121003101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31121003101 = 37781 ⋅823721.

It can be written as a sum of positive squares in 2 ways, for example, as 3867347344 + 6262664769 = 62188^2 + 79137^2 .

It is not a de Polignac number, because 10130012113 - 2²¹ = 10127914961 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (13), and also a Moran number because the ratio is a prime number: 779231701 = 10130012113 / (1 + 0 + 1 + 3 + 0 + 0 + 1 + 2 + 1 + 1 + 3).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10130012093 and 10130012102.

It is not an unprimeable number, because it can be changed into a prime (10130012143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 389615838 + ... + 389615863.

It is an arithmetic number, because the mean of its divisors is an integer number (2727310957).

Almost surely, 2^10130012113 is an apocalyptic number.

10130012113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

10130012113 is a deficient number, since it is larger than the sum of its proper divisors (779231715).

10130012113 is an equidigital number, since it uses as much as digits as its factorization.

10130012113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 779231714.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 10130012113 its reverse (31121003101), we get a palindrome (41251015214).

The spelling of 10130012113 in words is "ten billion, one hundred thirty million, twelve thousand, one hundred thirteen".