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10130013433 is a prime number
BaseRepresentation
bin10010110111100101…
…11011110011111001
3222010222102000000201
421123302323303321
5131221240412213
64353105202201
7506013456601
oct113362736371
928128360021
1010130013433
114329146031
121b68630361
13c5590c0b7
146c1527c01
153e44e06dd
hex25bcbbcf9

10130013433 has 2 divisors, whose sum is σ = 10130013434. Its totient is φ = 10130013432.

The previous prime is 10130013409. The next prime is 10130013473. The reversal of 10130013433 is 33431003101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8308687104 + 1821326329 = 91152^2 + 42677^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10130013433 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10130013433.

It is not a weakly prime, because it can be changed into another prime (10130013473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065006716 + 5065006717.

It is an arithmetic number, because the mean of its divisors is an integer number (5065006717).

Almost surely, 210130013433 is an apocalyptic number.

It is an amenable number.

10130013433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10130013433 is an equidigital number, since it uses as much as digits as its factorization.

10130013433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 10130013433 its reverse (33431003101), we get a palindrome (43561016534).

The spelling of 10130013433 in words is "ten billion, one hundred thirty million, thirteen thousand, four hundred thirty-three".