1013011313101 has 4 divisors (see below), whose sum is σ = 1017249854400. Its totient is φ = 1008772771804.

The previous prime is 1013011313029. The next prime is 1013011313113. The reversal of 1013011313101 is 1013131103101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1013011313101 is a prime.

It is a super-2 number, since 2×1013011313101² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1013011313131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2119270291 + ... + 2119270768.

It is an arithmetic number, because the mean of its divisors is an integer number (254312463600).

Almost surely, 2^{1013011313101} is an apocalyptic number.

It is an amenable number.

1013011313101 is a deficient number, since it is larger than the sum of its proper divisors (4238541299).

1013011313101 is an equidigital number, since it uses as much as digits as its factorization.

1013011313101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4238541298.

The product of its (nonzero) digits is 27, while the sum is 16.

Adding to 1013011313101 its reverse (1013131103101), we get a palindrome (2026142416202).

The spelling of 1013011313101 in words is "one trillion, thirteen billion, eleven million, three hundred thirteen thousand, one hundred one".