Base | Representation |
---|---|
bin | 10010110111100110… |
… | …10100001010111011 |
3 | 222010222121001220012 |
4 | 21123303110022323 |
5 | 131221302110321 |
6 | 4353111252135 |
7 | 506014353521 |
oct | 113363241273 |
9 | 28128531805 |
10 | 10130113211 |
11 | 4329203a99 |
12 | 1b6867a04b |
13 | c5594563a |
14 | 6c1552311 |
15 | 3e451005b |
hex | 25bcd42bb |
10130113211 has 2 divisors, whose sum is σ = 10130113212. Its totient is φ = 10130113210.
The previous prime is 10130113159. The next prime is 10130113223. The reversal of 10130113211 is 11231103101.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (11231103101) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10130113211 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (10130113241) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065056605 + 5065056606.
It is an arithmetic number, because the mean of its divisors is an integer number (5065056606).
Almost surely, 210130113211 is an apocalyptic number.
10130113211 is a deficient number, since it is larger than the sum of its proper divisors (1).
10130113211 is an equidigital number, since it uses as much as digits as its factorization.
10130113211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 14.
Adding to 10130113211 its reverse (11231103101), we get a palindrome (21361216312).
The spelling of 10130113211 in words is "ten billion, one hundred thirty million, one hundred thirteen thousand, two hundred eleven".
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