10130113313 has 2 divisors, whose sum is σ = 10130113314. Its totient is φ = 10130113312.

The previous prime is 10130113303. The next prime is 10130113349. The reversal of 10130113313 is 31331103101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10067513569 + 62599744 = 100337^2 + 7912^2 .

It is a cyclic number.

It is not a de Polignac number, because 10130113313 - 2¹⁴ = 10130096929 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10130113291 and 10130113300.

It is not a weakly prime, because it can be changed into another prime (10130113303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065056656 + 5065056657.

It is an arithmetic number, because the mean of its divisors is an integer number (5065056657).

Almost surely, 2^10130113313 is an apocalyptic number.

It is an amenable number.

10130113313 is a deficient number, since it is larger than the sum of its proper divisors (1).

10130113313 is an equidigital number, since it uses as much as digits as its factorization.

10130113313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 10130113313 its reverse (31331103101), we get a palindrome (41461216414).

The spelling of 10130113313 in words is "ten billion, one hundred thirty million, one hundred thirteen thousand, three hundred thirteen".