10130300011313 has 2 divisors, whose sum is σ = 10130300011314. Its totient is φ = 10130300011312.

The previous prime is 10130300011241. The next prime is 10130300011319. The reversal of 10130300011313 is 31311000303101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7577951884864 + 2552348126449 = 2752808^2 + 1597607^2 .

It is a cyclic number.

It is not a de Polignac number, because 10130300011313 - 2³² = 10126005044017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10130300011291 and 10130300011300.

It is not a weakly prime, because it can be changed into another prime (10130300011319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065150005656 + 5065150005657.

It is an arithmetic number, because the mean of its divisors is an integer number (5065150005657).

Almost surely, 2^{10130300011313} is an apocalyptic number.

It is an amenable number.

10130300011313 is a deficient number, since it is larger than the sum of its proper divisors (1).

10130300011313 is an equidigital number, since it uses as much as digits as its factorization.

10130300011313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 10130300011313 its reverse (31311000303101), we get a palindrome (41441300314414).

The spelling of 10130300011313 in words is "ten trillion, one hundred thirty billion, three hundred million, eleven thousand, three hundred thirteen".