Base | Representation |
---|---|
bin | 1001001101101010011000… |
… | …1000110100000000001111 |
3 | 1022212110010102200221201021 |
4 | 2103122212020310000033 |
5 | 2311433343433240413 |
6 | 33313445503255011 |
7 | 2063614531022266 |
oct | 223324610640017 |
9 | 38773112627637 |
10 | 10130320211983 |
11 | 3256276732154 |
12 | 11773a78aa467 |
13 | 5863924868aa |
14 | 27044ad4d5dd |
15 | 1287a5e5918d |
hex | 936a623400f |
10130320211983 has 2 divisors, whose sum is σ = 10130320211984. Its totient is φ = 10130320211982.
The previous prime is 10130320211927. The next prime is 10130320212007. The reversal of 10130320211983 is 38911202303101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10130320211983 - 213 = 10130320203791 is a prime.
It is a super-3 number, since 3×101303202119833 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10130320211483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065160105991 + 5065160105992.
It is an arithmetic number, because the mean of its divisors is an integer number (5065160105992).
Almost surely, 210130320211983 is an apocalyptic number.
10130320211983 is a deficient number, since it is larger than the sum of its proper divisors (1).
10130320211983 is an equidigital number, since it uses as much as digits as its factorization.
10130320211983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 34.
The spelling of 10130320211983 in words is "ten trillion, one hundred thirty billion, three hundred twenty million, two hundred eleven thousand, nine hundred eighty-three".
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