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1013045450113 is a prime number
BaseRepresentation
bin11101011110111100011…
…01101101010110000001
310120211211212201221210001
432233132031231112001
5113044204113400423
62053215303440001
7133122132151204
oct16573615552601
93524755657701
101013045450113
113606a2823724
12144402a56001
13746b6bc19a8
1437062c4393b
151b541b94cad
hexebde36d581

1013045450113 has 2 divisors, whose sum is σ = 1013045450114. Its totient is φ = 1013045450112.

The previous prime is 1013045450101. The next prime is 1013045450117. The reversal of 1013045450113 is 3110545403101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 742471742224 + 270573707889 = 861668^2 + 520167^2 .

It is an emirp because it is prime and its reverse (3110545403101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1013045450113 - 213 = 1013045441921 is a prime.

It is a super-2 number, since 2×10130454501132 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1013045450117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506522725056 + 506522725057.

It is an arithmetic number, because the mean of its divisors is an integer number (506522725057).

Almost surely, 21013045450113 is an apocalyptic number.

It is an amenable number.

1013045450113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1013045450113 is an equidigital number, since it uses as much as digits as its factorization.

1013045450113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3600, while the sum is 28.

The spelling of 1013045450113 in words is "one trillion, thirteen billion, forty-five million, four hundred fifty thousand, one hundred thirteen".