Base | Representation |
---|---|
bin | 11101011111000011000… |
… | …10000111111011010001 |
3 | 10120211222202111222001111 |
4 | 32233201202013323101 |
5 | 113044312342233041 |
6 | 2053225013133321 |
7 | 133123406356411 |
oct | 16574142077321 |
9 | 3524882458044 |
10 | 1013101133521 |
11 | 3607211a6474 |
12 | 14441962a241 |
13 | 746c55b9c59 |
14 | 3706a3ba641 |
15 | 1b5469e3981 |
hex | ebe1887ed1 |
1013101133521 has 2 divisors, whose sum is σ = 1013101133522. Its totient is φ = 1013101133520.
The previous prime is 1013101133507. The next prime is 1013101133581. The reversal of 1013101133521 is 1253311013101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 749542109121 + 263559024400 = 865761^2 + 513380^2 .
It is a cyclic number.
It is not a de Polignac number, because 1013101133521 - 211 = 1013101131473 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1013101133492 and 1013101133501.
It is not a weakly prime, because it can be changed into another prime (1013101133581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506550566760 + 506550566761.
It is an arithmetic number, because the mean of its divisors is an integer number (506550566761).
Almost surely, 21013101133521 is an apocalyptic number.
It is an amenable number.
1013101133521 is a deficient number, since it is larger than the sum of its proper divisors (1).
1013101133521 is an equidigital number, since it uses as much as digits as its factorization.
1013101133521 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 270, while the sum is 22.
Adding to 1013101133521 its reverse (1253311013101), we get a palindrome (2266412146622).
The spelling of 1013101133521 in words is "one trillion, thirteen billion, one hundred one million, one hundred thirty-three thousand, five hundred twenty-one".
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