10131023113 has 4 divisors (see below), whose sum is σ = 10225705680. Its totient is φ = 10036340548.

The previous prime is 10131023099. The next prime is 10131023143. The reversal of 10131023113 is 31132013101.

10131023113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10131023113 - 2⁵ = 10131023081 is a prime.

It is a super-2 number, since 2×10131023113² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10131023143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47341123 + ... + 47341336.

It is an arithmetic number, because the mean of its divisors is an integer number (2556426420).

Almost surely, 2^10131023113 is an apocalyptic number.

It is an amenable number.

10131023113 is a deficient number, since it is larger than the sum of its proper divisors (94682567).

10131023113 is an equidigital number, since it uses as much as digits as its factorization.

10131023113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 94682566.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 10131023113 its reverse (31132013101), we get a palindrome (41263036214).

The spelling of 10131023113 in words is "ten billion, one hundred thirty-one million, twenty-three thousand, one hundred thirteen".