1013104441231 has 2 divisors, whose sum is σ = 1013104441232. Its totient is φ = 1013104441230.

The previous prime is 1013104441207. The next prime is 1013104441267. The reversal of 1013104441231 is 1321444013101.

It is a weak prime.

It is an emirp because it is prime and its reverse (1321444013101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1013104441231 - 2⁷ = 1013104441103 is a prime.

It is a super-2 number, since 2×1013104441231² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1013104441196 and 1013104441205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1013104441831) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506552220615 + 506552220616.

It is an arithmetic number, because the mean of its divisors is an integer number (506552220616).

Almost surely, 2^{1013104441231} is an apocalyptic number.

1013104441231 is a deficient number, since it is larger than the sum of its proper divisors (1).

1013104441231 is an equidigital number, since it uses as much as digits as its factorization.

1013104441231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1013104441231 its reverse (1321444013101), we get a palindrome (2334548454332).

The spelling of 1013104441231 in words is "one trillion, thirteen billion, one hundred four million, four hundred forty-one thousand, two hundred thirty-one".