Base | Representation |
---|---|
bin | 10010110111101110… |
… | …01000010010100011 |
3 | 222011001110212111222 |
4 | 21123313020102203 |
5 | 131222031104443 |
6 | 4353144525255 |
7 | 506026016645 |
oct | 113367102243 |
9 | 28131425458 |
10 | 10131113123 |
11 | 432982726a |
12 | 1b68a8082b |
13 | c55c057c1 |
14 | 6c1732895 |
15 | 3e465b468 |
hex | 25bdc84a3 |
10131113123 has 2 divisors, whose sum is σ = 10131113124. Its totient is φ = 10131113122.
The previous prime is 10131113099. The next prime is 10131113129. The reversal of 10131113123 is 32131113101.
10131113123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10131113123 is a prime.
It is a super-2 number, since 2×101311131232 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10131113129) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065556561 + 5065556562.
It is an arithmetic number, because the mean of its divisors is an integer number (5065556562).
Almost surely, 210131113123 is an apocalyptic number.
10131113123 is a deficient number, since it is larger than the sum of its proper divisors (1).
10131113123 is an equidigital number, since it uses as much as digits as its factorization.
10131113123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 10131113123 its reverse (32131113101), we get a palindrome (42262226224).
The spelling of 10131113123 in words is "ten billion, one hundred thirty-one million, one hundred thirteen thousand, one hundred twenty-three".
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