10131132113 has 4 divisors (see below), whose sum is σ = 10297216308. Its totient is φ = 9965047920.

The previous prime is 10131132083. The next prime is 10131132119. The reversal of 10131132113 is 31123113101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 978000529 + 9153131584 = 31273^2 + 95672^2 .

It is a cyclic number.

It is not a de Polignac number, because 10131132113 - 2¹² = 10131128017 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10131132091 and 10131132100.

It is not an unprimeable number, because it can be changed into a prime (10131132119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 83042006 + ... + 83042127.

It is an arithmetic number, because the mean of its divisors is an integer number (2574304077).

Almost surely, 2^10131132113 is an apocalyptic number.

It is an amenable number.

10131132113 is a deficient number, since it is larger than the sum of its proper divisors (166084195).

10131132113 is an equidigital number, since it uses as much as digits as its factorization.

10131132113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 166084194.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 10131132113 its reverse (31123113101), we get a palindrome (41254245214).

The spelling of 10131132113 in words is "ten billion, one hundred thirty-one million, one hundred thirty-two thousand, one hundred thirteen".