Base | Representation |
---|---|
bin | 11101011111000101010… |
… | …11101111010001000011 |
3 | 10120212001002211101110021 |
4 | 32233202223233101003 |
5 | 113044332312244141 |
6 | 2053230542514311 |
7 | 133124032401652 |
oct | 16574253572103 |
9 | 3525032741407 |
10 | 1013120431171 |
11 | 360731087042 |
12 | 144423b95997 |
13 | 746c95b5794 |
14 | 3706cba1199 |
15 | 1b5485566d1 |
hex | ebe2aef443 |
1013120431171 has 2 divisors, whose sum is σ = 1013120431172. Its totient is φ = 1013120431170.
The previous prime is 1013120431153. The next prime is 1013120431231. The reversal of 1013120431171 is 1711340213101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1013120431171 - 29 = 1013120430659 is a prime.
It is a super-2 number, since 2×10131204311712 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1013120431121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506560215585 + 506560215586.
It is an arithmetic number, because the mean of its divisors is an integer number (506560215586).
Almost surely, 21013120431171 is an apocalyptic number.
1013120431171 is a deficient number, since it is larger than the sum of its proper divisors (1).
1013120431171 is an equidigital number, since it uses as much as digits as its factorization.
1013120431171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 25.
Adding to 1013120431171 its reverse (1711340213101), we get a palindrome (2724460644272).
The spelling of 1013120431171 in words is "one trillion, thirteen billion, one hundred twenty million, four hundred thirty-one thousand, one hundred seventy-one".
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