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10131211113 = 33377070371
BaseRepresentation
bin10010110111101111…
…00000001101101001
3222011001122211221020
421123313200031221
5131222042223423
64353151003053
7506026605432
oct113367401551
928131584836
1010131211113
114329893951
121b68b09489
13c55c3b29a
146c175a489
153e467a4e3
hex25bde0369

10131211113 has 4 divisors (see below), whose sum is σ = 13508281488. Its totient is φ = 6754140740.

The previous prime is 10131211109. The next prime is 10131211127. The reversal of 10131211113 is 31111213101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10131211113 - 22 = 10131211109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10131211092 and 10131211101.

It is not an unprimeable number, because it can be changed into a prime (10131211163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1688535183 + ... + 1688535188.

It is an arithmetic number, because the mean of its divisors is an integer number (3377070372).

Almost surely, 210131211113 is an apocalyptic number.

It is an amenable number.

10131211113 is a deficient number, since it is larger than the sum of its proper divisors (3377070375).

10131211113 is an equidigital number, since it uses as much as digits as its factorization.

10131211113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3377070374.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 10131211113 its reverse (31111213101), we get a palindrome (41242424214).

The spelling of 10131211113 in words is "ten billion, one hundred thirty-one million, two hundred eleven thousand, one hundred thirteen".

Divisors: 1 3 3377070371 10131211113