Base | Representation |
---|---|
bin | 10010110111101111… |
… | …00000001101110111 |
3 | 222011001122211221202 |
4 | 21123313200031313 |
5 | 131222042224002 |
6 | 4353151003115 |
7 | 506026605452 |
oct | 113367401567 |
9 | 28131584852 |
10 | 10131211127 |
11 | 4329893964 |
12 | 1b68b0949b |
13 | c55c3b2ab |
14 | 6c175a499 |
15 | 3e467a502 |
hex | 25bde0377 |
10131211127 has 2 divisors, whose sum is σ = 10131211128. Its totient is φ = 10131211126.
The previous prime is 10131211109. The next prime is 10131211147. The reversal of 10131211127 is 72111213101.
It is an a-pointer prime, because the next prime (10131211147) can be obtained adding 10131211127 to its sum of digits (20).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10131211127 - 214 = 10131194743 is a prime.
It is a super-2 number, since 2×101312111272 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10131211099 and 10131211108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10131211147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065605563 + 5065605564.
It is an arithmetic number, because the mean of its divisors is an integer number (5065605564).
Almost surely, 210131211127 is an apocalyptic number.
10131211127 is a deficient number, since it is larger than the sum of its proper divisors (1).
10131211127 is an equidigital number, since it uses as much as digits as its factorization.
10131211127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84, while the sum is 20.
Adding to 10131211127 its reverse (72111213101), we get a palindrome (82242424228).
The spelling of 10131211127 in words is "ten billion, one hundred thirty-one million, two hundred eleven thousand, one hundred twenty-seven".
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