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10131211331 = 19533221649
BaseRepresentation
bin10010110111101111…
…00000010001000011
3222011001122212020022
421123313200101003
5131222042230311
64353151004055
7506026606163
oct113367402103
928131585208
1010131211331
11432989402a
121b68b0962b
13c55c3b407
146c175a5a3
153e467a5db
hex25bde0443

10131211331 has 4 divisors (see below), whose sum is σ = 10664433000. Its totient is φ = 9597989664.

The previous prime is 10131211313. The next prime is 10131211529. The reversal of 10131211331 is 13311213101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10131211331 - 210 = 10131210307 is a prime.

It is a super-2 number, since 2×101312113312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10131216331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 266610806 + ... + 266610843.

It is an arithmetic number, because the mean of its divisors is an integer number (2666108250).

Almost surely, 210131211331 is an apocalyptic number.

10131211331 is a deficient number, since it is larger than the sum of its proper divisors (533221669).

10131211331 is an equidigital number, since it uses as much as digits as its factorization.

10131211331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 533221668.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 10131211331 its reverse (13311213101), we get a palindrome (23442424432).

The spelling of 10131211331 in words is "ten billion, one hundred thirty-one million, two hundred eleven thousand, three hundred thirty-one".

Divisors: 1 19 533221649 10131211331