Base | Representation |
---|---|
bin | 1001001101101110011100… |
… | …0110001001111011010111 |
3 | 1022212112221101101200000011 |
4 | 2103123213012021323113 |
5 | 2311443111432100031 |
6 | 33314145554101051 |
7 | 2063653533246142 |
oct | 223334706117327 |
9 | 38775841350004 |
10 | 10131410034391 |
11 | 3256785925928 |
12 | 117765087a787 |
13 | 5865071b2c19 |
14 | 27051199d059 |
15 | 12881b97e6b1 |
hex | 936e7189ed7 |
10131410034391 has 2 divisors, whose sum is σ = 10131410034392. Its totient is φ = 10131410034390.
The previous prime is 10131410034293. The next prime is 10131410034401. The reversal of 10131410034391 is 19343001413101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10131410034391 - 211 = 10131410032343 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10131410037391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065705017195 + 5065705017196.
It is an arithmetic number, because the mean of its divisors is an integer number (5065705017196).
Almost surely, 210131410034391 is an apocalyptic number.
10131410034391 is a deficient number, since it is larger than the sum of its proper divisors (1).
10131410034391 is an equidigital number, since it uses as much as digits as its factorization.
10131410034391 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 31.
Adding to 10131410034391 its reverse (19343001413101), we get a palindrome (29474411447492).
The spelling of 10131410034391 in words is "ten trillion, one hundred thirty-one billion, four hundred ten million, thirty-four thousand, three hundred ninety-one".
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