Base | Representation |
---|---|
bin | 1001001101101110011111… |
… | …0000000100011100111011 |
3 | 1022212112222011001220012001 |
4 | 2103123213300010130323 |
5 | 2311443122240201021 |
6 | 33314151025401431 |
7 | 2063654025531052 |
oct | 223334760043473 |
9 | 38775864056161 |
10 | 10131421022011 |
11 | 3256791050003 |
12 | 1177654499277 |
13 | 58650955c183 |
14 | 27051321d399 |
15 | 12881c900091 |
hex | 936e7c0473b |
10131421022011 has 8 divisors (see below), whose sum is σ = 10677549314880. Its totient is φ = 9586582289928.
The previous prime is 10131421022003. The next prime is 10131421022027. The reversal of 10131421022011 is 11022012413101.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 10131421022011 - 23 = 10131421022003 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (19).
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 10131421022011.
It is not an unprimeable number, because it can be changed into a prime (10131421002011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 322374061 + ... + 322405486.
It is an arithmetic number, because the mean of its divisors is an integer number (1334693664360).
Almost surely, 210131421022011 is an apocalyptic number.
10131421022011 is a deficient number, since it is larger than the sum of its proper divisors (546128292869).
10131421022011 is an equidigital number, since it uses as much as digits as its factorization.
10131421022011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 644780393.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 10131421022011 its reverse (11022012413101), we get a palindrome (21153433435112).
It can be divided in two parts, 1013142 and 1022011, that added together give a triangular number (2035153 = T2017).
The spelling of 10131421022011 in words is "ten trillion, one hundred thirty-one billion, four hundred twenty-one million, twenty-two thousand, eleven".
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