Base | Representation |
---|---|
bin | 11101011111001111001… |
… | …11100001101101100111 |
3 | 10120212020212121010222211 |
4 | 32233213213201231213 |
5 | 113100020010310114 |
6 | 2053243101104251 |
7 | 133126056132604 |
oct | 16574747415547 |
9 | 3525225533884 |
10 | 1013203213159 |
11 | 360773888405 |
12 | 144447858087 |
13 | 747107ab1c7 |
14 | 37079b8d6ab |
15 | 1b5509596c4 |
hex | ebe79e1b67 |
1013203213159 has 2 divisors, whose sum is σ = 1013203213160. Its totient is φ = 1013203213158.
The previous prime is 1013203213129. The next prime is 1013203213219. The reversal of 1013203213159 is 9513123023101.
It is a weak prime.
It is an emirp because it is prime and its reverse (9513123023101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1013203213159 - 233 = 1004613278567 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1013203213159.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1013203213109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506601606579 + 506601606580.
It is an arithmetic number, because the mean of its divisors is an integer number (506601606580).
Almost surely, 21013203213159 is an apocalyptic number.
1013203213159 is a deficient number, since it is larger than the sum of its proper divisors (1).
1013203213159 is an equidigital number, since it uses as much as digits as its factorization.
1013203213159 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4860, while the sum is 31.
The spelling of 1013203213159 in words is "one trillion, thirteen billion, two hundred three million, two hundred thirteen thousand, one hundred fifty-nine".
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