Base | Representation |
---|---|
bin | 1001001101110001000011… |
… | …0101000111001110100001 |
3 | 1022212121202011220021022101 |
4 | 2103130100311013032201 |
5 | 2312001030203204303 |
6 | 33314343245210401 |
7 | 2064010064531254 |
oct | 223342065071641 |
9 | 38777664807271 |
10 | 10132110209953 |
11 | 3257005085116 |
12 | 1177807260a01 |
13 | 5865b92841a4 |
14 | 27057a98109b |
15 | 12885d188d1d |
hex | 93710d473a1 |
10132110209953 has 2 divisors, whose sum is σ = 10132110209954. Its totient is φ = 10132110209952.
The previous prime is 10132110209951. The next prime is 10132110210007. The reversal of 10132110209953 is 35990201123101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8835536286369 + 1296573923584 = 2972463^2 + 1138672^2 .
It is a cyclic number.
It is not a de Polignac number, because 10132110209953 - 21 = 10132110209951 is a prime.
Together with 10132110209951, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (10132110209951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5066055104976 + 5066055104977.
It is an arithmetic number, because the mean of its divisors is an integer number (5066055104977).
Almost surely, 210132110209953 is an apocalyptic number.
It is an amenable number.
10132110209953 is a deficient number, since it is larger than the sum of its proper divisors (1).
10132110209953 is an equidigital number, since it uses as much as digits as its factorization.
10132110209953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14580, while the sum is 37.
The spelling of 10132110209953 in words is "ten trillion, one hundred thirty-two billion, one hundred ten million, two hundred nine thousand, nine hundred fifty-three".
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