Search a number
-
+
101321210019973 is a prime number
BaseRepresentation
bin10111000010011010101110…
…101110110100000010000101
3111021202012202100001122010011
4113002122232232310002011
5101240021314231114343
6555254153222430221
730225134016050566
oct2702325656640205
9437665670048104
10101321210019973
112a3140a1688299
12b444890292371
13446c71a50a158
141b03d8926016d
15baa8e57ca29d
hex5c26aebb4085

101321210019973 has 2 divisors, whose sum is σ = 101321210019974. Its totient is φ = 101321210019972.

The previous prime is 101321210019943. The next prime is 101321210020021. The reversal of 101321210019973 is 379910012123101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 97676100466884 + 3645109553089 = 9883122^2 + 1909217^2 .

It is a cyclic number.

It is not a de Polignac number, because 101321210019973 - 229 = 101320673149061 is a prime.

It is a super-2 number, since 2×1013212100199732 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101321210019943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50660605009986 + 50660605009987.

It is an arithmetic number, because the mean of its divisors is an integer number (50660605009987).

Almost surely, 2101321210019973 is an apocalyptic number.

It is an amenable number.

101321210019973 is a deficient number, since it is larger than the sum of its proper divisors (1).

101321210019973 is an equidigital number, since it uses as much as digits as its factorization.

101321210019973 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20412, while the sum is 40.

The spelling of 101321210019973 in words is "one hundred one trillion, three hundred twenty-one billion, two hundred ten million, nineteen thousand, nine hundred seventy-three".