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101323213414121 is a prime number
BaseRepresentation
bin10111000010011100100110…
…001001001001111011101001
3111021202101220221210121020102
4113002130212021021323221
5101240034420113222441
6555255124110235145
730225234453450056
oct2702344611117351
9437671827717212
10101323213414121
112a314a2a532a36
12b44514b1b5ab5
13446c9795a238a
141b040d936002d
15baa9b160d69b
hex5c2726249ee9

101323213414121 has 2 divisors, whose sum is σ = 101323213414122. Its totient is φ = 101323213414120.

The previous prime is 101323213414051. The next prime is 101323213414151. The reversal of 101323213414121 is 121414312323101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97520463810025 + 3802749604096 = 9875245^2 + 1950064^2 .

It is a cyclic number.

It is not a de Polignac number, because 101323213414121 - 218 = 101323213151977 is a prime.

It is not a weakly prime, because it can be changed into another prime (101323213414151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50661606707060 + 50661606707061.

It is an arithmetic number, because the mean of its divisors is an integer number (50661606707061).

Almost surely, 2101323213414121 is an apocalyptic number.

It is an amenable number.

101323213414121 is a deficient number, since it is larger than the sum of its proper divisors (1).

101323213414121 is an equidigital number, since it uses as much as digits as its factorization.

101323213414121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 101323213414121 its reverse (121414312323101), we get a palindrome (222737525737222).

The spelling of 101323213414121 in words is "one hundred one trillion, three hundred twenty-three billion, two hundred thirteen million, four hundred fourteen thousand, one hundred twenty-one".