Base | Representation |
---|---|
bin | 101111001011101011… |
… | …0001110010010011111 |
3 | 100200112101220201012011 |
4 | 1132113112032102133 |
5 | 3130002244324434 |
6 | 114314120452051 |
7 | 10214613654046 |
oct | 1362726162237 |
9 | 320471821164 |
10 | 101323433119 |
11 | 39a75488a87 |
12 | 1777901a027 |
13 | 9729a6066c |
14 | 4c92b2155d |
15 | 2980507e64 |
hex | 179758e49f |
101323433119 has 2 divisors, whose sum is σ = 101323433120. Its totient is φ = 101323433118.
The previous prime is 101323433093. The next prime is 101323433143. The reversal of 101323433119 is 911334323101.
It is a strong prime.
It is an emirp because it is prime and its reverse (911334323101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 101323433119 - 29 = 101323432607 is a prime.
It is a super-2 number, since 2×1013234331192 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101323431119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50661716559 + 50661716560.
It is an arithmetic number, because the mean of its divisors is an integer number (50661716560).
Almost surely, 2101323433119 is an apocalyptic number.
101323433119 is a deficient number, since it is larger than the sum of its proper divisors (1).
101323433119 is an equidigital number, since it uses as much as digits as its factorization.
101323433119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 31.
The spelling of 101323433119 in words is "one hundred one billion, three hundred twenty-three million, four hundred thirty-three thousand, one hundred nineteen".
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