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101324212019 is a prime number
BaseRepresentation
bin101111001011101100…
…1001100011100110011
3100200112110101021122022
41132113121030130303
53130002444241034
6114314145302055
710214623406642
oct1362731143463
9320473337568
10101324212019
1139a759701a8
121777933492b
139729c74054
144c92c85359
15298060db2e
hex179764c733

101324212019 has 2 divisors, whose sum is σ = 101324212020. Its totient is φ = 101324212018.

The previous prime is 101324212001. The next prime is 101324212021. The reversal of 101324212019 is 910212423101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101324212019 - 28 = 101324211763 is a prime.

It is a super-2 number, since 2×1013242120192 (a number of 23 digits) contains 22 as substring.

Together with 101324212021, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (101324212049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50662106009 + 50662106010.

It is an arithmetic number, because the mean of its divisors is an integer number (50662106010).

Almost surely, 2101324212019 is an apocalyptic number.

101324212019 is a deficient number, since it is larger than the sum of its proper divisors (1).

101324212019 is an equidigital number, since it uses as much as digits as its factorization.

101324212019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 26.

The spelling of 101324212019 in words is "one hundred one billion, three hundred twenty-four million, two hundred twelve thousand, nineteen".