1013243334041 has 4 divisors (see below), whose sum is σ = 1013723318784. Its totient is φ = 1012763349300.

The previous prime is 1013243334017. The next prime is 1013243334049. The reversal of 1013243334041 is 1404333423101.

It is a happy number.

1013243334041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1013243334041 is a prime.

It is a super-3 number, since 3×1013243334041³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1013243333995 and 1013243334013.

It is not an unprimeable number, because it can be changed into a prime (1013243334049) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 239989205 + ... + 239993426.

It is an arithmetic number, because the mean of its divisors is an integer number (253430829696).

Almost surely, 2^{1013243334041} is an apocalyptic number.

It is an amenable number.

1013243334041 is a deficient number, since it is larger than the sum of its proper divisors (479984743).

1013243334041 is an equidigital number, since it uses as much as digits as its factorization.

1013243334041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 479984742.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 1013243334041 its reverse (1404333423101), we get a palindrome (2417576757142).

The spelling of 1013243334041 in words is "one trillion, thirteen billion, two hundred forty-three million, three hundred thirty-four thousand, forty-one".