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101330131211 = 233434893267
BaseRepresentation
bin101111001011110111…
…1110001100100001011
3100200112212112000020122
41132113233301210023
53130011003144321
6114314520213455
710215024622031
oct1362757614413
9320485460218
10101330131211
1139a792433a1
121777b30a28b
13972b26732a
144c93986551
152980dcc8ab
hex1797bf190b

101330131211 has 4 divisors (see below), whose sum is σ = 101765024712. Its totient is φ = 100895237712.

The previous prime is 101330131207. The next prime is 101330131319. The reversal of 101330131211 is 112131033101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 101330131211 - 22 = 101330131207 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 101330131211.

It is not an unprimeable number, because it can be changed into a prime (101330130211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 217446401 + ... + 217446866.

It is an arithmetic number, because the mean of its divisors is an integer number (25441256178).

Almost surely, 2101330131211 is an apocalyptic number.

101330131211 is a deficient number, since it is larger than the sum of its proper divisors (434893501).

101330131211 is an equidigital number, since it uses as much as digits as its factorization.

101330131211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 434893500.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 101330131211 its reverse (112131033101), we get a palindrome (213461164312).

The spelling of 101330131211 in words is "one hundred one billion, three hundred thirty million, one hundred thirty-one thousand, two hundred eleven".

Divisors: 1 233 434893267 101330131211