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101330221032013 is a prime number
BaseRepresentation
bin10111000010100011000111…
…110101000110001001001101
3111021210002000022212110210211
4113002203013311012021031
5101240143243041011023
6555302243320002421
730225603224304661
oct2702430765061115
9437702008773724
10101330221032013
112a3179a610aa86
12b446586000411
13447052534483c
141b045a1d008a1
15baac7192ea0d
hex5c28c7d4624d

101330221032013 has 2 divisors, whose sum is σ = 101330221032014. Its totient is φ = 101330221032012.

The previous prime is 101330221031971. The next prime is 101330221032113. The reversal of 101330221032013 is 310230122033101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 99979461054729 + 1350759977284 = 9998973^2 + 1162222^2 .

It is an emirp because it is prime and its reverse (310230122033101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-101330221032013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101330221032113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50665110516006 + 50665110516007.

It is an arithmetic number, because the mean of its divisors is an integer number (50665110516007).

Almost surely, 2101330221032013 is an apocalyptic number.

It is an amenable number.

101330221032013 is a deficient number, since it is larger than the sum of its proper divisors (1).

101330221032013 is an equidigital number, since it uses as much as digits as its factorization.

101330221032013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 101330221032013 its reverse (310230122033101), we get a palindrome (411560343065114).

The spelling of 101330221032013 in words is "one hundred one trillion, three hundred thirty billion, two hundred twenty-one million, thirty-two thousand, thirteen".