101332011113 has 2 divisors, whose sum is σ = 101332011114. Its totient is φ = 101332011112.

The previous prime is 101332011103. The next prime is 101332011119. The reversal of 101332011113 is 311110233101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90196907584 + 11135103529 = 300328^2 + 105523^2 .

It is a cyclic number.

It is not a de Polignac number, because 101332011113 - 2¹² = 101332007017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101332011091 and 101332011100.

It is not a weakly prime, because it can be changed into another prime (101332011119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50666005556 + 50666005557.

It is an arithmetic number, because the mean of its divisors is an integer number (50666005557).

Almost surely, 2^101332011113 is an apocalyptic number.

It is an amenable number.

101332011113 is a deficient number, since it is larger than the sum of its proper divisors (1).

101332011113 is an equidigital number, since it uses as much as digits as its factorization.

101332011113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 101332011113 its reverse (311110233101), we get a palindrome (412442244214).

The spelling of 101332011113 in words is "one hundred one billion, three hundred thirty-two million, eleven thousand, one hundred thirteen".