Search a number
-
+
101332332113 = 769113175443
BaseRepresentation
bin101111001011111100…
…0001010111001010001
3100200120000122211022112
41132113320022321101
53130012034111423
6114315035315105
710215052416455
oct1362770127121
9320500584275
10101332332113
1139a7a506a21
121777bbaba95
13972b85803c
144c93d9a665
1529811b4a78
hex1797e0ae51

101332332113 has 4 divisors (see below), whose sum is σ = 101345515248. Its totient is φ = 101319148980.

The previous prime is 101332332071. The next prime is 101332332137. The reversal of 101332332113 is 311233233101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 101332332113 - 214 = 101332315729 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (101332332163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6580031 + ... + 6595412.

It is an arithmetic number, because the mean of its divisors is an integer number (25336378812).

Almost surely, 2101332332113 is an apocalyptic number.

It is an amenable number.

101332332113 is a deficient number, since it is larger than the sum of its proper divisors (13183135).

101332332113 is an equidigital number, since it uses as much as digits as its factorization.

101332332113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13183134.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 101332332113 its reverse (311233233101), we get a palindrome (412565565214).

The spelling of 101332332113 in words is "one hundred one billion, three hundred thirty-two million, three hundred thirty-two thousand, one hundred thirteen".

Divisors: 1 7691 13175443 101332332113