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1013330212212 = 223611384330891
BaseRepresentation
bin11101011111011110010…
…11111111010101110100
310120212120201120100221110
432233233023333111310
5113100300013242322
62053303435115020
7133132160454333
oct16575713772564
93525521510843
101013330212212
1136082953a6aa
121444822a2a70
1374730bb5a86
143708c9abd1a
151b55bb93c0c
hexebef2ff574

1013330212212 has 24 divisors (see below), whose sum is σ = 2403198428512. Its totient is φ = 332239413600.

The previous prime is 1013330212127. The next prime is 1013330212331. The reversal of 1013330212212 is 2122120333101.

It is a super-4 number, since 4×10133302122124 (a number of 49 digits) contains 4444 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 692164714 + ... + 692166177.

Almost surely, 21013330212212 is an apocalyptic number.

1013330212212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1013330212212 is an abundant number, since it is smaller than the sum of its proper divisors (1389868216300).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1013330212212 is a wasteful number, since it uses less digits than its factorization.

1013330212212 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1384330959 (or 1384330957 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 1013330212212 its reverse (2122120333101), we get a palindrome (3135450545313).

The spelling of 1013330212212 in words is "one trillion, thirteen billion, three hundred thirty million, two hundred twelve thousand, two hundred twelve".

Divisors: 1 2 3 4 6 12 61 122 183 244 366 732 1384330891 2768661782 4152992673 5537323564 8305985346 16611970692 84444184351 168888368702 253332553053 337776737404 506665106106 1013330212212