10133302141 has 4 divisors (see below), whose sum is σ = 10134040000. Its totient is φ = 10132564284.

The previous prime is 10133302117. The next prime is 10133302159. The reversal of 10133302141 is 14120333101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10133302141 - 2¹³ = 10133293949 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10133302181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 347931 + ... + 375928.

It is an arithmetic number, because the mean of its divisors is an integer number (2533510000).

Almost surely, 2^10133302141 is an apocalyptic number.

It is an amenable number.

10133302141 is a deficient number, since it is larger than the sum of its proper divisors (737859).

10133302141 is an equidigital number, since it uses as much as digits as its factorization.

10133302141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 737858.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 10133302141 its reverse (14120333101), we get a palindrome (24253635242).

The spelling of 10133302141 in words is "ten billion, one hundred thirty-three million, three hundred two thousand, one hundred forty-one".