Base | Representation |
---|---|
bin | 1001001101110101101001… |
… | …1011101010010111101111 |
3 | 1022212201221020110202100022 |
4 | 2103131122123222113233 |
5 | 2312011042313132033 |
6 | 33315110000152355 |
7 | 2064052510523255 |
oct | 223353233522757 |
9 | 38781836422308 |
10 | 10133345052143 |
11 | 3257589119355 |
12 | 1177ab09086bb |
13 | 586755057641 |
14 | 2706569805d5 |
15 | 1288d17a8098 |
hex | 9375a6ea5ef |
10133345052143 has 2 divisors, whose sum is σ = 10133345052144. Its totient is φ = 10133345052142.
The previous prime is 10133345052133. The next prime is 10133345052161. The reversal of 10133345052143 is 34125054333101.
It is a weak prime.
It is an emirp because it is prime and its reverse (34125054333101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10133345052143 - 210 = 10133345051119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10133345052133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5066672526071 + 5066672526072.
It is an arithmetic number, because the mean of its divisors is an integer number (5066672526072).
Almost surely, 210133345052143 is an apocalyptic number.
10133345052143 is a deficient number, since it is larger than the sum of its proper divisors (1).
10133345052143 is an equidigital number, since it uses as much as digits as its factorization.
10133345052143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64800, while the sum is 35.
Adding to 10133345052143 its reverse (34125054333101), we get a palindrome (44258399385244).
The spelling of 10133345052143 in words is "ten trillion, one hundred thirty-three billion, three hundred forty-five million, fifty-two thousand, one hundred forty-three".
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