101341411307 has 4 divisors (see below), whose sum is σ = 101353118160. Its totient is φ = 101329704456.

The previous prime is 101341411261. The next prime is 101341411309. The reversal of 101341411307 is 703114143101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 703114143101 = 141443 ⋅4971007.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101341411307 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101341411309) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5840432 + ... + 5857757.

It is an arithmetic number, because the mean of its divisors is an integer number (25338279540).

Almost surely, 2^101341411307 is an apocalyptic number.

101341411307 is a deficient number, since it is larger than the sum of its proper divisors (11706853).

101341411307 is an equidigital number, since it uses as much as digits as its factorization.

101341411307 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11706852.

The product of its (nonzero) digits is 1008, while the sum is 26.

Adding to 101341411307 its reverse (703114143101), we get a palindrome (804455554408).

The spelling of 101341411307 in words is "one hundred one billion, three hundred forty-one million, four hundred eleven thousand, three hundred seven".