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10134144013303 = 53831188258513
BaseRepresentation
bin1001001101111000101000…
…0011011101001111110111
31022212210222220212012000101
42103132022003131033313
52312014211331411203
633315321140454531
72064111351552142
oct223361203351767
938783886765011
1010134144013303
11325795910a732
1211780943aa447
1358685173571b
142706d0b19059
1512892b9c741d
hex9378a0dd3f7

10134144013303 has 4 divisors (see below), whose sum is σ = 10134332325648. Its totient is φ = 10133955700960.

The previous prime is 10134144013267. The next prime is 10134144013387. The reversal of 10134144013303 is 30331044143101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10134144013303 - 217 = 10134143882231 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10134144013403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94075426 + ... + 94183087.

It is an arithmetic number, because the mean of its divisors is an integer number (2533583081412).

Almost surely, 210134144013303 is an apocalyptic number.

10134144013303 is a deficient number, since it is larger than the sum of its proper divisors (188312345).

10134144013303 is an equidigital number, since it uses as much as digits as its factorization.

10134144013303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 188312344.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 10134144013303 its reverse (30331044143101), we get a palindrome (40465188156404).

The spelling of 10134144013303 in words is "ten trillion, one hundred thirty-four billion, one hundred forty-four million, thirteen thousand, three hundred three".

Divisors: 1 53831 188258513 10134144013303