Base | Representation |
---|---|
bin | 1001001101111001010111… |
… | …0011011001100100101101 |
3 | 1022212211111122202210000211 |
4 | 2103132111303121210231 |
5 | 2312020112312134131 |
6 | 33315352501422421 |
7 | 2064116264202025 |
oct | 223362563314455 |
9 | 38784448683024 |
10 | 10134341130541 |
11 | 3257a4a403841 |
12 | 117812a40aa11 |
13 | 586883520844 |
14 | 27070cd8aa85 |
15 | 12893de625b1 |
hex | 93795cd992d |
10134341130541 has 2 divisors, whose sum is σ = 10134341130542. Its totient is φ = 10134341130540.
The previous prime is 10134341130509. The next prime is 10134341130553. The reversal of 10134341130541 is 14503114343101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8992627510441 + 1141713620100 = 2998771^2 + 1068510^2 .
It is a cyclic number.
It is not a de Polignac number, because 10134341130541 - 25 = 10134341130509 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10134341130581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5067170565270 + 5067170565271.
It is an arithmetic number, because the mean of its divisors is an integer number (5067170565271).
Almost surely, 210134341130541 is an apocalyptic number.
It is an amenable number.
10134341130541 is a deficient number, since it is larger than the sum of its proper divisors (1).
10134341130541 is an equidigital number, since it uses as much as digits as its factorization.
10134341130541 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 10134341130541 its reverse (14503114343101), we get a palindrome (24637455473642).
The spelling of 10134341130541 in words is "ten trillion, one hundred thirty-four billion, three hundred forty-one million, one hundred thirty thousand, five hundred forty-one".
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